Version: 2.83.1 (Linux 64)
This bug requires no example file to reproduce.
Below is an example of the expected result (left) vs what you actually get (right):
The operator appears to only affect the locations of the curve control points and not their handles.
I imagine that the original code was not made to support this case.
But I will confirm for now.
This occurs because the pivot (center) of each handle that is used in the shear.
I'm not sure why this happens (CC @Campbell Barton (campbellbarton))
Maybe we could always use td->loc to shear curves:
diff --git a/source/blender/editors/transform/transform_mode_shear.c b/source/blender/editors/transform/transform_mode_shear.c index fa33c1550e7..1902ef8a513 100644 --- a/source/blender/editors/transform/transform_mode_shear.c +++ b/source/blender/editors/transform/transform_mode_shear.c @@ -40,6 +40,7 @@ #include "BLT_translation.h" #include "transform.h" +#include "transform_convert.h" #include "transform_mode.h" #include "transform_snap.h" @@ -125,6 +126,7 @@ static void applyShear(TransInfo *t, const int UNUSED(mval[2])) int i; char str[UI_MAX_DRAW_STR]; const bool is_local_center = transdata_check_local_center(t, t->around); + const bool transform_td_center = !is_local_center && t->data_type != TC_CURVE_VERTS; value = t->values[0]; @@ -178,12 +180,17 @@ static void applyShear(TransInfo *t, const int UNUSED(mval[2])) if (is_local_center) { center = td->center; - co = td->loc; } else { center = tc->center_local; + } + + if (transform_td_center) { co = td->center; } + else { + co = td->loc; + } sub_v3_v3v3(vec, co, center);